What is the answer to 2log_{10}(3x)+log_{10}(18x)=27 ?

The answer to 2log_{10}(3x)+log_{10}(18x)=27 is x=10^{(27-log_{10}(162))/3}

Solve for x: 2log_{10}(3x)+log_{10}(18x)=27

The solution is x=10^{(27-log_{10}(162))/3}

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2 lo g_{10} (3 x) + lo g_{10} (18 x) = 27

x = 1 0^{\frac{27 - l o g _{10} ( 162 )}{3}}

Decimal Notation

x = 183440402.71636 \dots

Solution steps

2 lo g_{10} (3 x) + lo g_{10} (18 x) = 27

Apply log rules

x = 1 0^{\frac{27 - l o g _{10} ( 162 )}{3}}

Verify Solutions:

x = 1 0^{\frac{27 - l o g _{10} ( 162 )}{3}}

True

The solution is

x = 1 0^{\frac{27 - l o g _{10} ( 162 )}{3}}

lo g_{6} (x) + lo g_{6} (x + 5) = 2

lo g_{10} (x) + lo g_{10} (2 x - 1) = lo g_{10} (6)

lo g_{10} (x) - lo g_{10} (2) = 1 + lo g_{10} (21 - x)

lo g_{3} (x) = - 1

lo g_{4} (x) + lo g_{10} (8 x) = 1

What is the answer to 2log_{10}(3x)+log_{10}(18x)=27 ?
The answer to 2log_{10}(3x)+log_{10}(18x)=27 is x=10^{(27-log_{10}(162))/3}
Solve for x: 2log_{10}(3x)+log_{10}(18x)=27
The solution is x=10^{(27-log_{10}(162))/3}