What is the answer to ln(2x+1)-ln(x-6)=0 ?

The answer to ln(2x+1)-ln(x-6)=0 is No Solution for x\in\mathbb{R}

Solve for x: ln(2x+1)-ln(x-6)=0

The solution is No Solution for x\in\mathbb{R}

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ln (2 x + 1) - ln (x - 6) = 0

No Solution for x \in R

Solution steps

ln (2 x + 1) - ln (x - 6) = 0

Add

ln (x - 6)

to both sides

ln (2 x + 1) - ln (x - 6) + ln (x - 6) = 0 + ln (x - 6)

Simplify

ln (2 x + 1) = ln (x - 6)

Apply log rules

2 x + 1 = x - 6

Solve

2 x + 1 = x - 6 : x = - 7

x = - 7

Verify Solutions:

x = - 7

False

The solution is

No Solution for x \in R

lo g_{10} (x) = 5

lo g_{2} (2 x + 7) = 4

lo g_{5} (x) = 1 + lo g_{10} (x^{25})

\frac{x}{lo g _{2} ( 4 x - 12 )} = 5

lo g_{3} (x - 2) = 2

What is the answer to ln(2x+1)-ln(x-6)=0 ?
The answer to ln(2x+1)-ln(x-6)=0 is No Solution for x\in\mathbb{R}
Solve for x: ln(2x+1)-ln(x-6)=0
The solution is No Solution for x\in\mathbb{R}