What is the answer to log_{2}(x)+log_{2}(x+3)= 1/4 ?

The answer to log_{2}(x)+log_{2}(x+3)= 1/4 is x=(-3+sqrt(9+4\sqrt[4]{2)})/2

Solve for x: log_{2}(x)+log_{2}(x+3)= 1/4

The solution is x=(-3+sqrt(9+4\sqrt[4]{2)})/2

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lo g_{2} (x) + lo g_{2} (x + 3) = \frac{1}{4}

Decimal Notation

x = 0.35450 \dots

Solution steps

lo g_{2} (x) + lo g_{2} (x + 3) = \frac{1}{4}

Apply log rules

Solve

Verify Solutions:

True

False

The solution is

lo g_{2} (2 x + 1) + x = lo g_{2} (6) + lo g_{2} (5)

lo g_{10} (x^{2}) + 3 lo g_{10} (x) = 10

lo g_{3} (x) lo g_{9} (x) = 2

lo g_{10} (x) = 3.4151

2 \cdot ln (\frac{( 3 x )}{( x )}) - ln (x + 1) = 2

What is the answer to log_{2}(x)+log_{2}(x+3)= 1/4 ?
The answer to log_{2}(x)+log_{2}(x+3)= 1/4 is x=(-3+sqrt(9+4\sqrt[4]{2)})/2
Solve for x: log_{2}(x)+log_{2}(x+3)= 1/4
The solution is x=(-3+sqrt(9+4\sqrt[4]{2)})/2