What is the answer to log_{10}(x+27^{log_{3}(2)})=1 ?

The answer to log_{10}(x+27^{log_{3}(2)})=1 is x=2

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log_{10}(x+27^{log_{3}(2)})=1

lo g_{10} (x + 2 7^{l o g_{3} (2)}) = 1

x = 2

Solution steps

lo g_{10} (x + 2 7^{l o g_{3} (2)}) = 1

Apply log rules

x + 8 = 10

Solve

x + 8 = 10 : x = 2

x = 2

d^{2} + d + 1 = lo g_{10} (x)

lo g_{3} (1 - 6 x) = lo g_{3} (17 - x^{2})

ln (x) + ln (x - 1) = 1

lo g_{3} (2 x + 3) - lo g_{3} (x + 2) = 4

ln (x^{2} - 3) = 4

What is the answer to log_{10}(x+27^{log_{3}(2)})=1 ?
The answer to log_{10}(x+27^{log_{3}(2)})=1 is x=2
Solve for x: log_{10}(x+27^{log_{3}(2)})=1
The solution is x=2