What is the answer to log_{17}(x^3+2x^2-x+15)=1 ?

The answer to log_{17}(x^3+2x^2-x+15)=1 is x=-2,x=-1,x=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{17}(x^3+2x^2-x+15)=1

lo g_{17} (x^{3} + 2 x^{2} - x + 15) = 1

x = - 2, x = - 1, x = 1

Solution steps

lo g_{17} (x^{3} + 2 x^{2} - x + 15) = 1

Apply log rules

x^{3} + 2 x^{2} - x + 15 = 17

Solve

x^{3} + 2 x^{2} - x + 15 = 17 : x = - 2, x = - 1, x = 1

x = - 2, x = - 1, x = 1

lo g_{4} (22 - 4 x) = 2

lo g_{2} (x^{5}) = lo g_{10} (2 x)^{4}

lo g_{5} (x^{2}) - 4 = 2 + ∣ lo g_{5} (x) - 3 ∣

lo g_{2} (x^{2}) = 8

lo g_{2} (x^{2}) = 2

What is the answer to log_{17}(x^3+2x^2-x+15)=1 ?
The answer to log_{17}(x^3+2x^2-x+15)=1 is x=-2,x=-1,x=1
Solve for x: log_{17}(x^3+2x^2-x+15)=1
The solution is x=-2,x=-1,x=1