What is the answer to log_{2}(x-1)+log_{3}(3)=2 ?

The answer to log_{2}(x-1)+log_{3}(3)=2 is x=3

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log_{2}(x-1)+log_{3}(3)=2

lo g_{2} (x - 1) + lo g_{3} (3) = 2

x = 3

Solution steps

lo g_{2} (x - 1) + lo g_{3} (3) = 2

Move

lo g_{3} (3)

to the right side

lo g_{2} (x - 1) = 2 - lo g_{3} (3)

Apply log rules

x - 1 = 2

Solve

x - 1 = 2 : x = 3

x = 3

Verify Solutions:

x = 3

True

The solution is

x = 3

lo g_{10} (x) + lo g_{10} (x + 7) = 8

lo g_{3} (3 x + 1) - lo g_{3} (x - 1) = 4

2 lo g_{10} (2 - x) - lo g_{10} (x + 5) = 1

lo g_{4} (3 x - 6) = lo g_{4} (2 - x)

lo g_{10} (2 x) = (4) + lo g_{10} (3)

What is the answer to log_{2}(x-1)+log_{3}(3)=2 ?
The answer to log_{2}(x-1)+log_{3}(3)=2 is x=3
Solve for x: log_{2}(x-1)+log_{3}(3)=2
The solution is x=3