What is the answer to log_{3}(4-4x)=1 ?

The answer to log_{3}(4-4x)=1 is x= 1/4

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log_{3}(4-4x)=1

lo g_{3} (4 - 4 x) = 1

x = \frac{1}{4}

Decimal Notation

x = 0.25

Solution steps

lo g_{3} (4 - 4 x) = 1

Apply log rules

4 - 4 x = 3

Solve

4 - 4 x = 3 : x = \frac{1}{4}

x = \frac{1}{4}

lo g_{4} (2 x - 32) = 5

lo g_{3} (x^{2} - x - 5) - lo g_{3} (x) = 1

lo g_{10} (98 + x^{2} - 12 x + 36) = 2

lo g_{10} (x - 2) + lo g_{10} (x + 2) = 2

73 = 18 lo g_{10} (\frac{17.176}{x})