What is the answer to log_{4}(8)+log_{4}(x+3)-log_{4}(x-1)=2 ?

The answer to log_{4}(8)+log_{4}(x+3)-log_{4}(x-1)=2 is x=5

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log_{4}(8)+log_{4}(x+3)-log_{4}(x-1)=2

lo g_{4} (8) + lo g_{4} (x + 3) - lo g_{4} (x - 1) = 2

x = 5

Solution steps

lo g_{4} (8) + lo g_{4} (x + 3) - lo g_{4} (x - 1) = 2

Apply log rules

8 (x + 3) = 16 (x - 1)

Solve

8 (x + 3) = 16 (x - 1) : x = 5

x = 5

Verify Solutions:

x = 5

True

The solution is

x = 5

lo g_{3} (3^{x} - 6) = x - 1

8 ln (x^{2}) = x

lo g_{5} (- 9 - 2 x) = 2

lo g_{3} (3 x - 1) - lo g_{3} (2 x + 3) = 1 + lo g_{3} (x)

lo g_{3} (x) + lo g_{3} (x + 6) = 3

What is the answer to log_{4}(8)+log_{4}(x+3)-log_{4}(x-1)=2 ?
The answer to log_{4}(8)+log_{4}(x+3)-log_{4}(x-1)=2 is x=5
Solve for x: log_{4}(8)+log_{4}(x+3)-log_{4}(x-1)=2
The solution is x=5