What is the answer to (-3x)log_{10}(x+8)=0 ?

The answer to (-3x)log_{10}(x+8)=0 is x=0,x=-7

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(-3x)log_{10}(x+8)=0

(- 3 x) lo g_{10} (x + 8) = 0

x = 0, x = - 7

Solution steps

(- 3 x) lo g_{10} (x + 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

- 3 x = 0 or lo g_{10} (x + 8) = 0

Solve

- 3 x = 0 : x = 0

Solve

lo g_{10} (x + 8) = 0 : x = - 7

Verify Solutions:

x = 0

True

, x = - 7

True

The solutions are

x = 0, x = - 7

x, ln (\frac{x}{x _{0}}) = u (t - t_{0})

2.8 = - lo g_{10} (h^{30})

2 ln (x) - 2 ln (x + 2) = 4 ln (x^{2})

ln (x^{2} - x - 1) = 0

lo g_{3} (2 x^{2} + 5 x + 4) - 7 = 2

What is the answer to (-3x)log_{10}(x+8)=0 ?
The answer to (-3x)log_{10}(x+8)=0 is x=0,x=-7
Solve for x: (-3x)log_{10}(x+8)=0
The solution is x=0,x=-7