What is the answer to log_{10}(x+2)+log_{10}(x-2)=1 ?

The answer to log_{10}(x+2)+log_{10}(x-2)=1 is x=sqrt(14)

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log_{10}(x+2)+log_{10}(x-2)=1

lo g_{10} (x + 2) + lo g_{10} (x - 2) = 1

x = 14

Decimal Notation

x = 3.74165 \dots

Solution steps

lo g_{10} (x + 2) + lo g_{10} (x - 2) = 1

Apply log rules

(x + 2) (x - 2) = 10

Solve

(x + 2) (x - 2) = 10 : x = 14, x = - 14

x = 14, x = - 14

Verify Solutions:

x = 14

True

, x = - 14

False

The solution is

x = 14

ln (8 - 2 x) = \frac{1}{2} ln (4 - x)

ln (x) = 3.47

lo g_{3} (2 x + 7) = 2

ln (x^{3}) - 4 ln (x) = 1

lo g_{2} (x) - lo g_{4} (x - 4) = 2

What is the answer to log_{10}(x+2)+log_{10}(x-2)=1 ?
The answer to log_{10}(x+2)+log_{10}(x-2)=1 is x=sqrt(14)
Solve for x: log_{10}(x+2)+log_{10}(x-2)=1
The solution is x=sqrt(14)