What is factor x^2+4xy+4y^2 ?

The solution to factor x^2+4xy+4y^2 is (x+2y)^2

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factor x^2+4xy+4y^2

factor

x^{2} + 4 x y + 4 y^{2}

(x + 2 y)^{2}

Solution steps

x^{2} + 4 x y + 4 y^{2}

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

4 y^{2} = (2 y)^{2}

4 x y = 2 x \cdot 2 y

= x^{2} + 2 x \cdot 2 y + (2 y)^{2}

Apply Perfect Square Formula:

a^{2} + 2 ab + b^{2} = (a + b)^{2}

x^{2} + 2 x \cdot 2 y + (2 y)^{2} = (x + 2 y)^{2}

= (x + 2 y)^{2}

1 - 0.35

x^{2} + 1 \leq 2 x

\frac{m ^{2} - 49}{m - 7}

v - 15 = - 27

- x^{3} + 4 x^{2} + 21 x