What is the answer to solvefor m, 1/2*log_{3}(m)+3log_{3}(n)=1 ?

The answer to solvefor m, 1/2*log_{3}(m)+3log_{3}(n)=1 is m= 9/(n^6) {n>0}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor m, 1/2*log_{3}(m)+3log_{3}(n)=1

solve for

m, \frac{1}{2} \cdot lo g_{3} (m) + 3 lo g_{3} (n) = 1

m = \frac{9}{n ^{6}} {n > 0}

Solution steps

\frac{1}{2} lo g_{3} (m) + 3 lo g_{3} (n) = 1

Move

3 lo g_{3} (n)

to the right side

\frac{1}{2} lo g_{3} (m) = 1 - 3 lo g_{3} (n)

Multiply both sides by

2

lo g_{3} (m) = 2 - 6 lo g_{3} (n)

Apply log rules

m = \frac{9}{n ^{6}}

Verify Solutions:

m = \frac{9}{n ^{6}} {n > 0}

The solution is

m = \frac{9}{n ^{6}} {n > 0}

lo g_{5} (x) - lo g_{5} (2 x - 1) - lo g_{10} (625) = 0

lo g_{2} (3 x) = 5

1 + lo g_{2} (x) + 4 \cdot lo g_{4} (x) - 2 = 4

lo g_{25} (x) = 3

lo g_{10} (9 x) = \frac{1}{2}

What is the answer to solvefor m, 1/2*log_{3}(m)+3log_{3}(n)=1 ?
The answer to solvefor m, 1/2*log_{3}(m)+3log_{3}(n)=1 is m= 9/(n^6) {n>0}