What is the answer to 2log_{10}(x)-log_{10}(2x+15)=0 ?

The answer to 2log_{10}(x)-log_{10}(2x+15)=0 is x=5

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2log_{10}(x)-log_{10}(2x+15)=0

2 lo g_{10} (x) - lo g_{10} (2 x + 15) = 0

x = 5

Solution steps

2 lo g_{10} (x) - lo g_{10} (2 x + 15) = 0

Apply log rules

x^{2} = 2 x + 15

Solve

x^{2} = 2 x + 15 : x = 5, x = - 3

x = 5, x = - 3

Verify Solutions:

x = 5

True

, x = - 3

False

The solution is

x = 5

lo g_{4} (m) = 0

lo g_{4} (x) = 0

lo g_{10} (10 x + 5) = lo g_{10} (9 x + 3)

lo g_{4} (x) = 6

x \cdot ln (x^{6}) = 16 ln (x)

What is the answer to 2log_{10}(x)-log_{10}(2x+15)=0 ?
The answer to 2log_{10}(x)-log_{10}(2x+15)=0 is x=5
Solve for x: 2log_{10}(x)-log_{10}(2x+15)=0
The solution is x=5