What is the answer to log_{2}(x+7)+log_{2}(x+1)=4 ?

The answer to log_{2}(x+7)+log_{2}(x+1)=4 is x=1

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log_{2}(x+7)+log_{2}(x+1)=4

lo g_{2} (x + 7) + lo g_{2} (x + 1) = 4

x = 1

Solution steps

lo g_{2} (x + 7) + lo g_{2} (x + 1) = 4

Apply log rules

(x + 7) (x + 1) = 16

Solve

(x + 7) (x + 1) = 16 : x = 1, x = - 9

x = 1, x = - 9

Verify Solutions:

x = 1

True

, x = - 9

False

The solution is

x = 1

lo g_{10} (n) + lo g_{10} (5) = 1

lo g_{2} (x^{2}) + 3 lo g_{2} (x) = 10

ln (7 x + 6) - ln (x) = ln (8)

lo g_{2} (x - 1) + lo g_{2} (x + 3) = 5

lo g_{2} (2 x) - lo g_{2} (x + 1) = 0

What is the answer to log_{2}(x+7)+log_{2}(x+1)=4 ?
The answer to log_{2}(x+7)+log_{2}(x+1)=4 is x=1
Solve for x: log_{2}(x+7)+log_{2}(x+1)=4
The solution is x=1