What is the answer to 2.3log_{10}((t^1)/(t^2))=0.69825 ?

The answer to 2.3log_{10}((t^1)/(t^2))=0.69825 is t= 2/(4.02361…)

Solve for t: 2.3log_{10}((t^1)/(t^2))=0.69825

The solution is t= 2/(4.02361…)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2.3 lo g_{10} (\frac{t ^{1}}{t ^{2}}) = 0.69825

t = \frac{2}{4.02361 \dots}

Decimal Notation

t = 0.49706 \dots

Solution steps

2.3 lo g_{10} (\frac{t ^{1}}{t ^{2}}) = 0.69825

Divide both sides by

2.3

lo g_{10} (\frac{t ^{1}}{t ^{2}}) = \frac{0.69825}{2.3}

Apply log rules

\frac{t ^{1}}{t ^{2}} = 1 0^{\frac{0.69825}{2.3}}

Multiply both sides by

t^{2}

\frac{t ^{1}}{t ^{2}} t^{2} = 1 0^{\frac{0.69825}{2.3}} t^{2}

Simplify

t = 1 0^{\frac{0.69825}{2.3}} t^{2}

Simplify

t = 2.01180 \dots t^{2}

Solve

t = 2.01180 \dots t^{2} : t = \frac{2}{4.02361 \dots}, t = 0

t = \frac{2}{4.02361 \dots}, t = 0

Verify Solutions:

t = \frac{2}{4.02361 \dots}

True

, t = 0

False

The solution is

t = \frac{2}{4.02361 \dots}

lo g_{10} (1 + x) = 1 + lo g_{10} (x)

ln (x + 1) = - 2

lo g_{2} (x) - lo g_{2} (x + 1) = 3

lo g_{6} (2 x + 16) = 3

- 3.75 = lo g_{10} (y)

What is the answer to 2.3log_{10}((t^1)/(t^2))=0.69825 ?
The answer to 2.3log_{10}((t^1)/(t^2))=0.69825 is t= 2/(4.02361…)
Solve for t: 2.3log_{10}((t^1)/(t^2))=0.69825
The solution is t= 2/(4.02361…)