What is the answer to ln(r)-ln(b)=2ln(a)-ln(c) ?

The answer to ln(r)-ln(b)=2ln(a)-ln(c) is r=(ba^2)/c

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ln(r)-ln(b)=2ln(a)-ln(c)

ln (r) - ln (b) = 2 ln (a) - ln (c)

r = \frac{b a ^{2}}{c}

Solution steps

ln (r) - ln (b) = 2 ln (a) - ln (c)

Move

ln (b)

to the right side

ln (r) = 2 ln (a) - ln (c) + ln (b)

Apply log rules

r = \frac{b a ^{2}}{c}

lo g_{10} (x + 2) - lo g_{10} (x) = 1

0.051 = lo g_{10} (x)

- lo g_{10} (b + 98) = 0.125

x, 2 y^{2} + 3 y - 5 x = ln (x + y^{2}) - 1

lo g_{7} (x) = lo g_{7} (a) \cdot b^{2} - lo g_{7} (a^{3} \cdot b)

What is the answer to ln(r)-ln(b)=2ln(a)-ln(c) ?
The answer to ln(r)-ln(b)=2ln(a)-ln(c) is r=(ba^2)/c