What is the answer to log_{10}(x)+log_{10}(x+3)=2log_{10}(x+1) ?

The answer to log_{10}(x)+log_{10}(x+3)=2log_{10}(x+1) is x=1

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log_{10}(x)+log_{10}(x+3)=2log_{10}(x+1)

lo g_{10} (x) + lo g_{10} (x + 3) = 2 lo g_{10} (x + 1)

x = 1

Solution steps

lo g_{10} (x) + lo g_{10} (x + 3) = 2 lo g_{10} (x + 1)

Apply log rules

x (x + 3) = (x + 1)^{2}

Solve

x (x + 3) = (x + 1)^{2} : x = 1

x = 1

Verify Solutions:

x = 1

True

The solution is

x = 1

x, (lo g_{2} (x))^{2} = \frac{1}{f}

2 lo g_{10} (x) = 3 + lo g_{10} (x)

lo g_{10} (10 m) = 4

lo g_{5} (x^{2} + x + 5) = 2

\frac{( lo g _{10} ( 2 x ^{2} + 1 ) )}{( lo g _{10} ( x + 1 ) )} = 2

What is the answer to log_{10}(x)+log_{10}(x+3)=2log_{10}(x+1) ?
The answer to log_{10}(x)+log_{10}(x+3)=2log_{10}(x+1) is x=1
Solve for x: log_{10}(x)+log_{10}(x+3)=2log_{10}(x+1)
The solution is x=1