What are the solutions to the equation 7x^2=5 ?

The solutions to the equation 7x^2=5 are x=sqrt(5/7),x=-sqrt(5/7)

Find the zeros of 7x^2=5

The zeros of 7x^2=5 are x=sqrt(5/7),x=-sqrt(5/7)

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7 x^{2} = 5

x = \frac{5}{7}, x = - \frac{5}{7}

Solution steps

7 x^{2} = 5

Divide both sides by

7

x^{2} = \frac{5}{7}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{5}{7}, x = - \frac{5}{7}

x^{2} + 11 x y - 12 y^{2}

4 x^{2} - 7 x - 15

4 < \frac{3 x - 10}{x + 7} < 24

8 ln (1)

\frac{x + 1}{x} < 1

What are the solutions to the equation 7x^2=5 ?
The solutions to the equation 7x^2=5 are x=sqrt(5/7),x=-sqrt(5/7)
Find the zeros of 7x^2=5
The zeros of 7x^2=5 are x=sqrt(5/7),x=-sqrt(5/7)