What is the answer to solvefor b,ln(12b)=2ln(b+3a)-ln(a) ?

The answer to solvefor b,ln(12b)=2ln(b+3a)-ln(a) is b=3a {a>0}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor b,ln(12b)=2ln(b+3a)-ln(a)

solve for

b, ln (12 b) = 2 ln (b + 3 a) - ln (a)

b = 3 a {a > 0}

Solution steps

ln (12 b) = 2 ln (b + 3 a) - ln (a)

Apply log rules

12 ba = (b + 3 a)^{2}

Solve

12 ba = (b + 3 a)^{2} : b = 3 a

b = 3 a

Verify Solutions:

b = 3 a {a > 0}

The solution is

b = 3 a {a > 0}

\frac{lo g _{10} ( 80 )}{lo g _{10} ( 2 x )} = \frac{lo g _{10} ( 500 )}{lo g _{10} ( 5 x )}

lo g_{5} ((x - 2)^{2}) \cdot lo g_{2} (5) = 2

20 lo g_{10} (x) = 28

lo g_{a} (2) = \frac{1}{6}

ln^{2} (x) = ln (e)

What is the answer to solvefor b,ln(12b)=2ln(b+3a)-ln(a) ?
The answer to solvefor b,ln(12b)=2ln(b+3a)-ln(a) is b=3a {a>0}