What is the answer to 1/(2log_{10)(7x-3)}=-5 ?

The answer to 1/(2log_{10)(7x-3)}=-5 is x=(1+3\sqrt[10]{10})/(7\sqrt[10]{10)}

Solve for x: 1/(2log_{10)(7x-3)}=-5

The solution is x=(1+3\sqrt[10]{10})/(7\sqrt[10]{10)}

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\frac{1}{2 lo g _{10} ( 7 x - 3 )} = - 5

Decimal Notation

x = 0.54204 \dots

Solution steps

\frac{1}{2 lo g _{10} ( 7 x - 3 )} = - 5

Rewrite the equation with

lo g_{10} (7 x - 3) = u

\frac{1}{2 u} = - 5

Solve

\frac{1}{2 u} = - 5 : u = - \frac{1}{10}

u = - \frac{1}{10}

Substitute back

u = lo g_{10} (7 x - 3),

solve for

x

Solve

Verify Solutions:

True

The solution is

x, ln (y - x^{2}) = k

lo g_{5} (x^{3}) + 13 x - 5 = 0

lo g_{2} (x - 1) + x = 1

lo g_{x} (x^{2}) = lo g_{8} (16 x)

lo g_{10} (x) = 18

What is the answer to 1/(2log_{10)(7x-3)}=-5 ?
The answer to 1/(2log_{10)(7x-3)}=-5 is x=(1+3\sqrt[10]{10})/(7\sqrt[10]{10)}
Solve for x: 1/(2log_{10)(7x-3)}=-5
The solution is x=(1+3\sqrt[10]{10})/(7\sqrt[10]{10)}