What is the answer to log_{10}(x)+x=0 ?

The answer to log_{10}(x)+x=0 is x=(\W_{0}(ln(10)))/(ln(10))

Solve for x: log_{10}(x)+x=0

The solution is x=(\W_{0}(ln(10)))/(ln(10))

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lo g_{10} (x) + x = 0

x = \frac{W _{0} ( ln ( 10 ) )}{ln ( 10 )}

Decimal Notation

x = 0.39901 \dots

Solution steps

lo g_{10} (x) + x = 0

Move

x

to the right side

lo g_{10} (x) = - x

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

1 0^{l o g_{10} (x)} = 1 0^{- x}

Simplify

1 0^{l o g_{10} (x)} : x

x = 1 0^{- x}

Solve

x = 1 0^{- x} : x = \frac{W _{0} ( ln ( 10 ) )}{ln ( 10 )}

x = \frac{W _{0} ( ln ( 10 ) )}{ln ( 10 )}

Verify Solutions:

x = \frac{W _{0} ( ln ( 10 ) )}{ln ( 10 )}

True

The solution is

x = \frac{W _{0} ( ln ( 10 ) )}{ln ( 10 )}

lo g_{x} (5) - lo g_{25} (x) - 1 = 0

lo g_{10} (x) + lo g_{10} (x - 2) = 2 lo g_{10} (x - 4)

lo g_{10} (a) 5 = 5

- ln (5 - x) = 2.2

lo g_{3} (x) + lo g_{3} (x - 8) = 2

What is the answer to log_{10}(x)+x=0 ?
The answer to log_{10}(x)+x=0 is x=(\W_{0}(ln(10)))/(ln(10))
Solve for x: log_{10}(x)+x=0
The solution is x=(\W_{0}(ln(10)))/(ln(10))