What is the answer to log_{10}(x+2)-log_{10}(9)=log_{10}(15) ?

The answer to log_{10}(x+2)-log_{10}(9)=log_{10}(15) is x=133

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log_{10}(x+2)-log_{10}(9)=log_{10}(15)

lo g_{10} (x + 2) - lo g_{10} (9) = lo g_{10} (15)

x = 133

Solution steps

lo g_{10} (x + 2) - lo g_{10} (9) = lo g_{10} (15)

Move

lo g_{10} (9)

to the right side

lo g_{10} (x + 2) = lo g_{10} (15) + lo g_{10} (9)

Apply log rules

x + 2 = 135

Solve

x + 2 = 135 : x = 133

x = 133

Verify Solutions:

x = 133

True

The solution is

x = 133

lo g_{10} (x) = - 1

lo g_{10} (x) = - 5

lo g_{3} (5 x - 4) = 3

2 lo g_{10} (x) = lo g_{2} (x)

lo g_{10} (x + 8) = 0

What is the answer to log_{10}(x+2)-log_{10}(9)=log_{10}(15) ?
The answer to log_{10}(x+2)-log_{10}(9)=log_{10}(15) is x=133
Solve for x: log_{10}(x+2)-log_{10}(9)=log_{10}(15)
The solution is x=133