What is the answer to solvefor a,log_{3}(a)+1=2log_{10}(b) ?

The answer to solvefor a,log_{3}(a)+1=2log_{10}(b) is a=3^{2log_{10}(b)-1} {b>0}

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solvefor a,log_{3}(a)+1=2log_{10}(b)

solve for

a, lo g_{3} (a) + 1 = 2 lo g_{10} (b)

a = 3^{2 l o g_{10} (b) - 1} {b > 0}

Solution steps

lo g_{3} (a) + 1 = 2 lo g_{10} (b)

Move

1

to the right side

lo g_{3} (a) = 2 lo g_{10} (b) - 1

Apply log rules

a = 3^{2 l o g_{10} (b) - 1}

Verify Solutions:

a = 3^{2 l o g_{10} (b) - 1} {b > 0}

The solution is

a = 3^{2 l o g_{10} (b) - 1} {b > 0}

lo g_{2} (3 - x) = lo g_{4} (2 x^{18})

2 lo g_{10} (x) = lo g_{10} (10 - 3 x)

ln (x) + 5 = 10

lo g_{3} (x + 1) - lo g_{3} (27) = 4

lo g_{10} (n) = 2.5955

What is the answer to solvefor a,log_{3}(a)+1=2log_{10}(b) ?
The answer to solvefor a,log_{3}(a)+1=2log_{10}(b) is a=3^{2log_{10}(b)-1} {b>0}