What is the answer to ln(x-2)=x+1 ?

The answer to ln(x-2)=x+1 is No Solution for x\in\mathbb{R}

Solve for x: ln(x-2)=x+1

The solution is No Solution for x\in\mathbb{R}

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ln (x - 2) = x + 1

No Solution for x \in R

Solution steps

ln (x - 2) = x + 1

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

e^{l n (x - 2)} = e^{x + 1}

Simplify

e^{l n (x - 2)} : x - 2

x - 2 = e^{x + 1}

Solve

x - 2 = e^{x + 1} :

No Solution for

x \in R

No Solution for x \in R

lo g_{10} (8 x) = \frac{11}{16}

lo g_{2} (x - l) = 2 \cdot lo g_{2} (x - 3)

lo g_{3} (x - 4) = 2

9 lo g_{3} (4 x - 6) = lo g_{3} (x)

(ln (x))^{2} - 3 ln (x^{4}) = 28

What is the answer to ln(x-2)=x+1 ?
The answer to ln(x-2)=x+1 is No Solution for x\in\mathbb{R}
Solve for x: ln(x-2)=x+1
The solution is No Solution for x\in\mathbb{R}