What is 9x+16y=7,4y-3x=0 ?

The solution to 9x+16y=7,4y-3x=0 is x= 1/3 ,y= 1/4

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9x+16y=7,4y-3x=0

9 x + 16 y = 7, 4 y - 3 x = 0

x = \frac{1}{3}, y = \frac{1}{4}

Solution steps

[9 x + 16 y = 7 4 y - 3 x = 0]

Isolate

x

for

9 x + 16 y = 7 : x = \frac{7 - 16 y}{9}

Substitute

x = \frac{7 - 16 y}{9}

[4 y - 3 \cdot \frac{7 - 16 y}{9} = 0]

Simplify

[\frac{- 7 + 28 y}{3} = 0]

Isolate

y

for

\frac{- 7 + 28 y}{3} = 0 : y = \frac{1}{4}

For

x = \frac{7 - 16 y}{9}

Substitute

y = \frac{1}{4}

x = \frac{7 - 16 \cdot \frac{1}{4}}{9}

\frac{7 - 16 \cdot \frac{1}{4}}{9} = \frac{1}{3}

x = \frac{1}{3}

The solutions to the system of equations are:

x = \frac{1}{3}, y = \frac{1}{4}

2 x + 3 y = 3, x + 5 y = - 9

3 x - y = 0, - 4 x + y = - 2

3 x + y = - 4, 3 x - 4 y = 6

u = 1 - 1, w = 37 w, v = 11

3 x + 2 y = 5, 2 x - 3 y = 7