What is 2x-3y+7=5,x+2y+8=0 ?

The solution to 2x-3y+7=5,x+2y+8=0 is x=-4,y=-2

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2x-3y+7=5,x+2y+8=0

2 x - 3 y + 7 = 5, x + 2 y + 8 = 0

x = - 4, y = - 2

Solution steps

[2 x - 3 y + 7 = 5 x + 2 y + 8 = 0]

Isolate

x

for

2 x - 3 y + 7 = 5 : x = \frac{3 y - 2}{2}

Substitute

x = \frac{3 y - 2}{2}

[\frac{3 y - 2}{2} + 2 y + 8 = 0]

Simplify

[\frac{7 y - 2}{2} + 8 = 0]

Isolate

y

for

\frac{7 y - 2}{2} + 8 = 0 : y = - 2

For

x = \frac{3 y - 2}{2}

Substitute

y = - 2

x = \frac{3 ( - 2 ) - 2}{2}

\frac{3 ( - 2 ) - 2}{2} = - 4

x = - 4

The solutions to the system of equations are:

x = - 4, y = - 2

x + 2 y = - 1, 2 x - 3 y = 12

5 x - 6 y - z = 12, 4 x - 3 y + 4 z = 15

3 x - 5 y = 4, 9 x - 2 y = 7

x - y = 3, 2 x + y = 12

4 x + 6 y = 24, 2 x + 3 y = 6