What is 2y-x^2=3,y-x=1 ?

The solution to 2y-x^2=3,y-x=1 is

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2y-x^2=3,y-x=1

2 y - x^{2} = 3, y - x = 1

(x = 1, y = 2)

Solution steps

[2 y - x^{2} = 3 y - x = 1]

Isolate

y

for

y - x = 1 : y = 1 + x

Plug the solutions

y = 1 + x

into

2 y - x^{2} = 3

For

2 y - x^{2} = 3

, subsitute

y

with

1 + x : x = 1

Plug the solutions

x = 1

into

y - x = 1

For

y - x = 1

, subsitute

x

with

1 : y = 2

Verify solutions by plugging them into the original equations

Therefore, the final solution for

2 y - x^{2} = 3, y - x = 1

(x = 1, y = 2)

x + 5 y = 5, 3 x - 5 y = 3

- 3 x + 2 y = - 1, 4 x - y = - \frac{1}{2}

12 x + 8 y = - 92, - 2.5 y + x = - 33

83 x + 71 y = 35, 71 x + 83 y = 472

x + y = 7, x + 3 y = 15