What are the solutions to the equation x^2+4x-5=0,x=1-1 ?

The solutions to the equation x^2+4x-5=0,x=1-1 are No Solution

Find the zeros of x^2+4x-5=0,x=1-1

The zeros of x^2+4x-5=0,x=1-1 are No Solution

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x^{2} + 4 x - 5 = 0, x = 1 - 1

No Solution

Solution steps

x^{2} + 4 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 5) = 6

x_{1, 2} = \frac{- 4 \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 6}{2 \cdot 1}, x_{2} = \frac{- 4 - 6}{2 \cdot 1}

x = \frac{- 4 + 6}{2 \cdot 1} : 1

x = \frac{- 4 - 6}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 1, x = - 5

Check constrains

No Solution

3 x + 2 y = 3, - x + 5 y = 16

5 x + 3 y = - 11, 2 x + 4 y = - 10

x + 2 y = 6, 3 x - y = 4

x + 3 y = 7, 2 x + y = - 1

p (x) = 2, x + 1 x = \frac{1}{2}

What are the solutions to the equation x^2+4x-5=0,x=1-1 ?
The solutions to the equation x^2+4x-5=0,x=1-1 are No Solution
Find the zeros of x^2+4x-5=0,x=1-1
The zeros of x^2+4x-5=0,x=1-1 are No Solution