What are the solutions to the equation a^2-10a+5=-4 ?

The solutions to the equation a^2-10a+5=-4 are a=9,a=1

Find the zeros of a^2-10a+5=-4

The zeros of a^2-10a+5=-4 are a=9,a=1

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a^{2} - 10 a + 5 = - 4

a = 9, a = 1

Solution steps

a^{2} - 10 a + 5 = - 4

Move

4

to the left side

a^{2} - 10 a + 9 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 9 = 8

a_{1, 2} = \frac{- ( - 10 ) \pm 8}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 10 ) + 8}{2 \cdot 1}, a_{2} = \frac{- ( - 10 ) - 8}{2 \cdot 1}

a = \frac{- ( - 10 ) + 8}{2 \cdot 1} : 9

a = \frac{- ( - 10 ) - 8}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

a = 9, a = 1

q^{\frac{3}{2}}

42 a^{4} b^{6}

\frac{x}{3} + \frac{1}{2} = \frac{2}{3}

5 x^{2} + 7 = 0

18 y = 8

What are the solutions to the equation a^2-10a+5=-4 ?
The solutions to the equation a^2-10a+5=-4 are a=9,a=1
Find the zeros of a^2-10a+5=-4
The zeros of a^2-10a+5=-4 are a=9,a=1