What is p-2q=3,3p+6q=4 ?

The solution to p-2q=3,3p+6q=4 is p= 13/6 ,q=-5/12

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p-2q=3,3p+6q=4

p - 2 q = 3, 3 p + 6 q = 4

p = \frac{13}{6}, q = - \frac{5}{12}

Solution steps

[p - 2 q = 3 3 p + 6 q = 4]

Isolate

p

for

p - 2 q = 3 : p = 3 + 2 q

Substitute

p = 3 + 2 q

[3 (3 + 2 q) + 6 q = 4]

Simplify

[9 + 12 q = 4]

Isolate

q

for

9 + 12 q = 4 : q = - \frac{5}{12}

For

p = 3 + 2 q

Substitute

q = - \frac{5}{12}

p = 3 + 2 (- \frac{5}{12})

3 + 2 (- \frac{5}{12}) = \frac{13}{6}

p = \frac{13}{6}

The solutions to the system of equations are:

p = \frac{13}{6}, q = - \frac{5}{12}

2 x + y = 4, 4 x - 3 y = 3

x - 2 y = - 4, 2 x - y = 1

5 x - 4 y + 8 = 7, x + 6 y - 9 = 0

11 x + 15 y + 23 = 7, x - 2 y - 20 = 0

2 x + 5 y = - 1, 3 x - y = 7