What is x+y+z=6,x-y+z=2,x-z=-2 ?

The solution to x+y+z=6,x-y+z=2,x-z=-2 is x=1,y=2,z=3

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x+y+z=6,x-y+z=2,x-z=-2

x + y + z = 6, x - y + z = 2, x - z = - 2

x = 1, y = 2, z = 3

Solution steps

x + y + z = 6 x - y + z = 2 x - z = - 2

Isolate

x

for

x - z = - 2 : x = - 2 + z

Substitute

x = - 2 + z

[- 2 + z + y + z = 6 - 2 + z - y + z = 2]

Simplify

[2 z + y - 2 = 6 2 z - y - 2 = 2]

Isolate

z

for

2 z + y - 2 = 6 : z = \frac{- y + 8}{2}

Substitute

z = \frac{- y + 8}{2}

[2 \cdot \frac{- y + 8}{2} - y - 2 = 2]

Simplify

[- 2 y + 6 = 2]

Isolate

y

for

- 2 y + 6 = 2 : y = 2

For

z = \frac{- y + 8}{2}

Substitute

y = 2

z = \frac{- 2 + 8}{2}

\frac{- 2 + 8}{2} = 3

z = 3

For

x = - 2 + z

Substitute

y = 2, z = 3

x = - 2 + 3

Simplify

x = 1

The solutions to the system of equations are:

x = 1, y = 2, z = 3

3 (x + y) = 2 x - 1, x + y = - 5

2 x + 3 y = 53, 3 x - y = 19

4 x + 6 y = 2, 6 x + 5 y = 1

5 x - 3 y = - 16, 5 x + 3 y = 2

2 x + y = 5, x - y = 1

What is x+y+z=6,x-y+z=2,x-z=-2 ?
The solution to x+y+z=6,x-y+z=2,x-z=-2 is x=1,y=2,z=3