What is x+2y-3z=4,y+2z=3,z=1 ?

The solution to x+2y-3z=4,y+2z=3,z=1 is x=5,y=1,z=1

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x+2y-3z=4,y+2z=3,z=1

x + 2 y - 3 z = 4, y + 2 z = 3, z = 1

x = 5, y = 1, z = 1

Solution steps

x + 2 y - 3 z = 4 y + 2 z = 3 z = 1

Substitute

z = 1

[y + 2 \cdot 1 = 3 x + 2 y - 3 \cdot 1 = 4]

Simplify

[y + 2 = 3 x + 2 y - 3 = 4]

Isolate

y

for

y + 2 = 3 : y = 1

Substitute

y = 1

[x + 2 \cdot 1 - 3 = 4]

Simplify

[x - 1 = 4]

Isolate

x

for

x - 1 = 4 : x = 5

The solutions to the system of equations are:

x = 5, y = 1, z = 1

5 x - y = 3, 2 x + 4 y = - 12

2 x + 4 y - 2 = 4, x + 8 y - 10 = 0

3 x + 8 = 2, x - a = 0

3 b = 3, a = 1

6 x - 3 y = - 10, 3 x + 5 y - 8 = 0

What is x+2y-3z=4,y+2z=3,z=1 ?
The solution to x+2y-3z=4,y+2z=3,z=1 is x=5,y=1,z=1