What is 7x+3y=15,12y-5x=39 ?

The solution to 7x+3y=15,12y-5x=39 is x= 7/11 ,y= 116/33

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7x+3y=15,12y-5x=39

7 x + 3 y = 15, 12 y - 5 x = 39

x = \frac{7}{11}, y = \frac{116}{33}

Solution steps

[7 x + 3 y = 15 12 y - 5 x = 39]

Isolate

x

for

7 x + 3 y = 15 : x = \frac{15 - 3 y}{7}

Substitute

x = \frac{15 - 3 y}{7}

[12 y - 5 \cdot \frac{15 - 3 y}{7} = 39]

Simplify

[\frac{- 75 + 99 y}{7} = 39]

Isolate

y

for

\frac{- 75 + 99 y}{7} = 39 : y = \frac{116}{33}

For

x = \frac{15 - 3 y}{7}

Substitute

y = \frac{116}{33}

x = \frac{15 - 3 \cdot \frac{116}{33}}{7}

\frac{15 - 3 \cdot \frac{116}{33}}{7} = \frac{7}{11}

x = \frac{7}{11}

The solutions to the system of equations are:

x = \frac{7}{11}, y = \frac{116}{33}

- x + y = 1, - 2 x + 4 y = - 8

a + b = 1, a - b = 16

x + 7 y = 10, 2 x + y = 13

x + y = 9, 2 x - y = 3

2 x + y - 2 z = 10, 3 x + 2 y + 2 z = 1, 5 x + 4 y + 3 z = 4

What is 7x+3y=15,12y-5x=39 ?
The solution to 7x+3y=15,12y-5x=39 is x= 7/11 ,y= 116/33