What is 2x-3y+2=0,6x+9y+5=0 ?

The solution to 2x-3y+2=0,6x+9y+5=0 is x=-11/12 ,y= 1/18

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2x-3y+2=0,6x+9y+5=0

2 x - 3 y + 2 = 0, 6 x + 9 y + 5 = 0

x = - \frac{11}{12}, y = \frac{1}{18}

Solution steps

[2 x - 3 y + 2 = 0 6 x + 9 y + 5 = 0]

Isolate

x

for

2 x - 3 y + 2 = 0 : x = \frac{3 y - 2}{2}

Substitute

x = \frac{3 y - 2}{2}

[6 \cdot \frac{3 y - 2}{2} + 9 y + 5 = 0]

Simplify

[18 y - 1 = 0]

Isolate

y

for

18 y - 1 = 0 : y = \frac{1}{18}

For

x = \frac{3 y - 2}{2}

Substitute

y = \frac{1}{18}

x = \frac{3 \cdot \frac{1}{18} - 2}{2}

\frac{3 \cdot \frac{1}{18} - 2}{2} = - \frac{11}{12}

x = - \frac{11}{12}

The solutions to the system of equations are:

x = - \frac{11}{12}, y = \frac{1}{18}

7 m + 13 n = 27, 13 m + 7 n = 33

5 x + 7 y = - 1, - 3 x + 4 y = - 24

2 x - 3 y = 5, x + y = 10

x + y = 9, 2 x - 3 y = - 7

2 x + y = 10, 3 x + 4 y = 25

What is 2x-3y+2=0,6x+9y+5=0 ?
The solution to 2x-3y+2=0,6x+9y+5=0 is x=-11/12 ,y= 1/18