What is ((x+3))/2-((y-1))/3 =1,((x+y))/5 =1 ?

The solution to ((x+3))/2-((y-1))/3 =1,((x+y))/5 =1 is x=1,y=4

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((x+3))/2-((y-1))/3 =1,((x+y))/5 =1

\frac{( x + 3 )}{2} - \frac{( y - 1 )}{3} = 1, \frac{( x + y )}{5} = 1

x = 1, y = 4

Solution steps

[\frac{( x + 3 )}{2} - \frac{( y - 1 )}{3} = 1 \frac{( x + y )}{5} = 1]

Isolate

x

for

\frac{( x + 3 )}{2} - \frac{( y - 1 )}{3} = 1 : x = \frac{2 ( y - 1 )}{3} - 1

Substitute

x = \frac{2 ( y - 1 )}{3} - 1

[\frac{\frac{2 ( y - 1 )}{3} - 1 + y}{5} = 1]

Simplify

[\frac{y - 1}{3} = 1]

Isolate

y

for

\frac{y - 1}{3} = 1 : y = 4

For

x = \frac{2 ( y - 1 )}{3} - 1

Substitute

y = 4

x = \frac{2 ( 4 - 1 )}{3} - 1

\frac{2 ( 4 - 1 )}{3} - 1 = 1

x = 1

The solutions to the system of equations are:

x = 1, y = 4

f (y, x, h) y = 2, 3 x - 53 h y = - 1, 4 x + 23 j y = 23 x - 113

2 x + 4 y = 34, 5 x + 4 y = 37

2 x + 2 y = 1, 3 - x + 4 y = 6

0.3 e q = 3.5, p = 2

3 - 2 (3 x + 4 y) = x, \frac{( x - 3 )}{4} - \frac{( y - 4 )}{5} = \frac{21}{10}

What is ((x+3))/2-((y-1))/3 =1,((x+y))/5 =1 ?
The solution to ((x+3))/2-((y-1))/3 =1,((x+y))/5 =1 is x=1,y=4