What is x/2-y/5 =4, x/7+y/(15)=3 ?

The solution to x/2-y/5 =4, x/7+y/(15)=3 is x=14,y=15

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x/2-y/5 =4, x/7+y/(15)=3

\frac{x}{2} - \frac{y}{5} = 4, \frac{x}{7} + \frac{y}{15} = 3

x = 14, y = 15

Solution steps

[\frac{x}{2} - \frac{y}{5} = 4 \frac{x}{7} + \frac{y}{15} = 3]

Isolate

x

for

\frac{x}{2} - \frac{y}{5} = 4 : x = 8 + \frac{2 y}{5}

Substitute

x = 8 + \frac{2 y}{5}

[\frac{8 + \frac{2 y}{5}}{7} + \frac{y}{15} = 3]

Simplify

[\frac{120 + 13 y}{105} = 3]

Isolate

y

for

\frac{120 + 13 y}{105} = 3 : y = 15

For

x = 8 + \frac{2 y}{5}

Substitute

y = 15

x = 8 + \frac{2 \cdot 15}{5}

8 + \frac{2 \cdot 15}{5} = 14

x = 14

The solutions to the system of equations are:

x = 14, y = 15

8 x - 2 y = 7, 2 x + 3 y = 5

x + y = 16, 2 x - y = 23

(4) 3 x - y - 2 = 0, 2 x + y = 8

3 x + 4 y = 20, 2 x - 3 y = 2

2 x + 7 y - 3 = 5, x + 4 y + 6 = 0

What is x/2-y/5 =4, x/7+y/(15)=3 ?
The solution to x/2-y/5 =4, x/7+y/(15)=3 is x=14,y=15