What is w(x,z,y)+x+z=5,y+z=8,x+z=2 ?

The solution to w(x,z,y)+x+z=5,y+z=8,x+z=2 is x=2-z,y=8-z,w=3

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w(x,z,y)+x+z=5,y+z=8,x+z=2

w (x, z, y) + x + z = 5, y + z = 8, x + z = 2

x = 2 - z, y = 8 - z, w = 3

Solution steps

w + x + z = 5 y + z = 8 x + z = 2

Isolate

y

for

y + z = 8 : y = 8 - z

[x + z = 2 w + x + z = 5]

Isolate

x

for

x + z = 2 : x = 2 - z

Substitute

x = 2 - z

[w + 2 - z + z = 5]

Simplify

[w + 2 = 5]

Isolate

w

for

w + 2 = 5 : w = 3

Expressing

x

in terms of

z

x = 2 - z

Expressing

y

in terms of

z

y = 8 - z

The solutions to the system of equations are:

x = 2 - z, y = 8 - z, w = 3

2 x - y = 2, 2 x + y = 13

2 y - 3 x = 1, - 4 y + 6 x = - 2

2 x + 3 y = 2, (k + 2) x + (2 k + 1) y = 2 (k - 1)

3 x + 2 y = 16, 5 x - 3 y = - 5

6 x + y = 25, 2 x + y = 13

What is w(x,z,y)+x+z=5,y+z=8,x+z=2 ?
The solution to w(x,z,y)+x+z=5,y+z=8,x+z=2 is x=2-z,y=8-z,w=3