What is 3x+2y=1,1x-4y=13 ?

The solution to 3x+2y=1,1x-4y=13 is x= 15/7 ,y=-19/7

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3x+2y=1,1x-4y=13

3 x + 2 y = 1, 1 x - 4 y = 13

x = \frac{15}{7}, y = - \frac{19}{7}

Solution steps

[3 x + 2 y = 1 1 \cdot x - 4 y = 13]

Isolate

x

for

3 x + 2 y = 1 : x = \frac{1 - 2 y}{3}

Substitute

x = \frac{1 - 2 y}{3}

[1 \cdot \frac{1 - 2 y}{3} - 4 y = 13]

Simplify

[\frac{1 - 14 y}{3} = 13]

Isolate

y

for

\frac{1 - 14 y}{3} = 13 : y = - \frac{19}{7}

For

x = \frac{1 - 2 y}{3}

Substitute

y = - \frac{19}{7}

x = \frac{1 - 2 ( - \frac{19}{7} )}{3}

\frac{1 - 2 ( - \frac{19}{7} )}{3} = \frac{15}{7}

x = \frac{15}{7}

The solutions to the system of equations are:

x = \frac{15}{7}, y = - \frac{19}{7}

2 x + y = 1, - x + 2 y = 9

x + 2 y = 3, 2 x + y = 6

x + 2 y = 9, 3 x - 2 y = - 5

x + y = 6, x = 1 y - 2

2 x + 3 y = 13, 2 x + y = 7