What is 11x+13y=1,7x-y=0 ?

The solution to 11x+13y=1,7x-y=0 is x= 1/102 ,y= 7/102

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11x+13y=1,7x-y=0

11 x + 13 y = 1, 7 x - y = 0

x = \frac{1}{102}, y = \frac{7}{102}

Solution steps

[11 x + 13 y = 1 7 x - y = 0]

Isolate

x

for

11 x + 13 y = 1 : x = \frac{1 - 13 y}{11}

Substitute

x = \frac{1 - 13 y}{11}

[7 \cdot \frac{1 - 13 y}{11} - y = 0]

Simplify

[\frac{7 - 102 y}{11} = 0]

Isolate

y

for

\frac{7 - 102 y}{11} = 0 : y = \frac{7}{102}

For

x = \frac{1 - 13 y}{11}

Substitute

y = \frac{7}{102}

x = \frac{1 - 13 \cdot \frac{7}{102}}{11}

\frac{1 - 13 \cdot \frac{7}{102}}{11} = \frac{1}{102}

x = \frac{1}{102}

The solutions to the system of equations are:

x = \frac{1}{102}, y = \frac{7}{102}

x + y = 8, 4 x - 3 y = - 10

3 x - 2 y = - 14, 2 x + 3 y = 8

2 x + 4 y + 3 z = 31, 0 x - 8 y - 9 z = 4, x + 4 y - 3 z = 2

23 p + 27 q = 10, 27 p + 23 q = 100

2 x + y = - 1, 0 x - 3 y = 2

What is 11x+13y=1,7x-y=0 ?
The solution to 11x+13y=1,7x-y=0 is x= 1/102 ,y= 7/102