What is 2x-3y=30,3x-4y-5=0 ?

The solution to 2x-3y=30,3x-4y-5=0 is x=-105,y=-80

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2x-3y=30,3x-4y-5=0

2 x - 3 y = 30, 3 x - 4 y - 5 = 0

x = - 105, y = - 80

Solution steps

[2 x - 3 y = 30 3 x - 4 y - 5 = 0]

Isolate

x

for

2 x - 3 y = 30 : x = \frac{30 + 3 y}{2}

Substitute

x = \frac{30 + 3 y}{2}

[3 \cdot \frac{30 + 3 y}{2} - 4 y - 5 = 0]

Simplify

[\frac{90 + y}{2} - 5 = 0]

Isolate

y

for

\frac{90 + y}{2} - 5 = 0 : y = - 80

For

x = \frac{30 + 3 y}{2}

Substitute

y = - 80

x = \frac{30 + 3 ( - 80 )}{2}

\frac{30 + 3 ( - 80 )}{2} = - 105

x = - 105

The solutions to the system of equations are:

x = - 105, y = - 80

2 x + y = 5, x - 3 y = 6

8 x + 5 y = 9, 3 x + 2 y = 4

3 x + 2 y = 4, 9 x + 6 y = 12

4 x - y = 12, 2 x + 3 y = - 5

3 x - 4 y = 10, 4 x + 3 y = 5