What is 5x+7y=1,6*3x+8y=12 ?

The solution to 5x+7y=1,6*3x+8y=12 is x= 38/43 ,y=-21/43

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5x+7y=1,6*3x+8y=12

5 x + 7 y = 1, 6 \cdot 3 x + 8 y = 12

x = \frac{38}{43}, y = - \frac{21}{43}

Solution steps

[5 x + 7 y = 1 6 \cdot 3 x + 8 y = 12]

Isolate

x

for

5 x + 7 y = 1 : x = \frac{1 - 7 y}{5}

Substitute

x = \frac{1 - 7 y}{5}

[6 \cdot 3 \cdot \frac{1 - 7 y}{5} + 8 y = 12]

Simplify

[\frac{18 - 86 y}{5} = 12]

Isolate

y

for

\frac{18 - 86 y}{5} = 12 : y = - \frac{21}{43}

For

x = \frac{1 - 7 y}{5}

Substitute

y = - \frac{21}{43}

x = \frac{1 - 7 ( - \frac{21}{43} )}{5}

\frac{1 - 7 ( - \frac{21}{43} )}{5} = \frac{38}{43}

x = \frac{38}{43}

The solutions to the system of equations are:

x = \frac{38}{43}, y = - \frac{21}{43}

2 x + 3 y = 12, 2 x = 3 y

x = y + 5, x + y = 31

9 x - 7 y = - 52, 5 x + 3 y = - 22

3 x - y = 14, 2 y = 12

4 x = 3, 3 x - y = - 6

What is 5x+7y=1,6*3x+8y=12 ?
The solution to 5x+7y=1,6*3x+8y=12 is x= 38/43 ,y=-21/43