What is 12(x+2y)-8(2x+y)=2,(5x-6y)20(x-4y)=-10 ?

The solution to 12(x+2y)-8(2x+y)=2,(5x-6y)20(x-4y)=-10 is

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12(x+2y)-8(2x+y)=2,(5x-6y)20(x-4y)=-10

12 (x + 2 y) - 8 (2 x + y) = 2, (5 x - 6 y) 20 (x - 4 y) = - 10

(x = \frac{1}{2}, y = \frac{1}{4})

Solution steps

[12 (x + 2 y) - 8 (2 x + y) = 2 (5 x - 6 y) \cdot 20 (x - 4 y) = - 10]

Isolate

x

for

(5 x - 6 y) 20 (x - 4 y) = - 10 : x = \frac{520 y + 78400 y ^{2} - 4000}{200}, x = \frac{520 y - 78400 y ^{2} - 4000}{200}

Plug the solutions

x = \frac{520 y + 78400 y ^{2} - 4000}{200}, x = \frac{520 y - 78400 y ^{2} - 4000}{200}

into

12 (x + 2 y) - 8 (2 x + y) = 2

For

12 (x + 2 y) - 8 (2 x + y) = 2

, subsitute

x

with

\frac{520 y + 78400 y ^{2} - 4000}{200} :

No Solution for

y \in R

For

12 (x + 2 y) - 8 (2 x + y) = 2

, subsitute

x

with

\frac{520 y - 78400 y ^{2} - 4000}{200} : y = \frac{1}{4}

Plug the solutions

y = \frac{1}{4}

into

(5 x - 6 y) 20 (x - 4 y) = - 10

For

(5 x - 6 y) 20 (x - 4 y) = - 10

, subsitute

y

with

\frac{1}{4} : x = \frac{4}{5}, x = \frac{1}{2}

Verify solutions by plugging them into the original equations

Therefore, the final solution for

12 (x + 2 y) - 8 (2 x + y) = 2, (5 x - 6 y) 20 (x - 4 y) = - 10

(x = \frac{1}{2}, y = \frac{1}{4})

x + 3 y = 11, 4 x - y = 5

x - y = 8, 3 x - 3 y = 16

3 x - 4 \frac{y}{2} = 10, 3 x + 2 \frac{y}{4} = 2

x - 2 y + 3 z = 2, 3 x - y + 4 z = 4, 2 x + y - 2 z = 5

x - y + 3 z - t = 5, - 2 z + t = 6, - 3 t = - 12

What is 12(x+2y)-8(2x+y)=2,(5x-6y)20(x-4y)=-10 ?
The solution to 12(x+2y)-8(2x+y)=2,(5x-6y)20(x-4y)=-10 is