What is x+y+z=4,2x+5y-2z=3 ?

The solution to x+y+z=4,2x+5y-2z=3 is x=(-7z+5)/3+4,y=(4z-5)/3

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x+y+z=4,2x+5y-2z=3

x + y + z = 4, 2 x + 5 y - 2 z = 3

x = \frac{- 7 z + 5}{3} + 4, y = \frac{4 z - 5}{3}

Solution steps

[x + y + z = 4 2 x + 5 y - 2 z = 3]

Isolate

x

for

x + y + z = 4 : x = 4 - y - z

Substitute

x = 4 - y - z

[2 (4 - y - z) + 5 y - 2 z = 3]

Simplify

[3 y - 4 z + 8 = 3]

Isolate

y

for

3 y - 4 z + 8 = 3 : y = \frac{4 z - 5}{3}

For

x = 4 - y - z

Expressing

x

in terms of

z

x = 4 - \frac{4 z - 5}{3} - z

Simplify

4 - \frac{4 z - 5}{3} - z : \frac{- 7 z + 5}{3} + 4

x = \frac{- 7 z + 5}{3} + 4

The solutions to the system of equations are:

x = \frac{- 7 z + 5}{3} + 4, y = \frac{4 z - 5}{3}

- 5 x + y = 6, 5 x - 7 y = 18

72 x + 3 y = 6, 3 x - 2 y = 7

- 7 x + 6 y = - 2, 9 x + 3 y = 8

x - y = 2, 3 x + 4 y = 27

x + 2 y = 2, 3 x - 4 y = 6

What is x+y+z=4,2x+5y-2z=3 ?
The solution to x+y+z=4,2x+5y-2z=3 is x=(-7z+5)/3+4,y=(4z-5)/3