What is 15x+4y=35,100x-9y=90 ?

The solution to 15x+4y=35,100x-9y=90 is x= 135/107 ,y= 430/107

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15x+4y=35,100x-9y=90

15 x + 4 y = 35, 100 x - 9 y = 90

x = \frac{135}{107}, y = \frac{430}{107}

Solution steps

[15 x + 4 y = 35 100 x - 9 y = 90]

Isolate

x

for

15 x + 4 y = 35 : x = \frac{35 - 4 y}{15}

Substitute

x = \frac{35 - 4 y}{15}

[100 \cdot \frac{35 - 4 y}{15} - 9 y = 90]

Simplify

[\frac{- 107 y + 700}{3} = 90]

Isolate

y

for

\frac{- 107 y + 700}{3} = 90 : y = \frac{430}{107}

For

x = \frac{35 - 4 y}{15}

Substitute

y = \frac{430}{107}

x = \frac{35 - 4 \cdot \frac{430}{107}}{15}

\frac{35 - 4 \cdot \frac{430}{107}}{15} = \frac{135}{107}

x = \frac{135}{107}

The solutions to the system of equations are:

x = \frac{135}{107}, y = \frac{430}{107}

x = 7, y = 2

5 a - 6 b = 9, 4 a - 6 b = 6

2 x + 3 y - 17 = 0, x - 2 y + 9 = 0

3 x + 4 y = 17, 4 x - 3 y = 6

\frac{1}{2} x + \frac{1}{3} y = 2, \frac{1}{3} x + \frac{1}{2} y = \frac{13}{6}

What is 15x+4y=35,100x-9y=90 ?
The solution to 15x+4y=35,100x-9y=90 is x= 135/107 ,y= 430/107