What is x+y-z+t=6,y+z=1,z+2t=6,2t=8 ?

The solution to x+y-z+t=6,y+z=1,z+2t=6,2t=8 is t=4,x=-3,y=3,z=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x+y-z+t=6,y+z=1,z+2t=6,2t=8

x + y - z + t = 6, y + z = 1, z + 2 t = 6, 2 t = 8

t = 4, x = - 3, y = 3, z = - 2

Solution steps

x + y - z + t = 6 y + z = 1 z + 2 t = 6 2 t = 8

Isolate

t

for

2 t = 8 : t = 4

Substitute

t = 4

y + z = 1 z + 2 \cdot 4 = 6 x + y - z + 4 = 6

Simplify

y + z = 1 z + 8 = 6 x + y - z + 4 = 6

Isolate

z

for

z + 8 = 6 : z = - 2

Substitute

z = - 2

[y - 2 = 1 x + y - (- 2) + 4 = 6]

Simplify

[y - 2 = 1 x + y + 6 = 6]

Isolate

y

for

y - 2 = 1 : y = 3

Substitute

y = 3

[x + 3 + 6 = 6]

Simplify

[x + 9 = 6]

Isolate

x

for

x + 9 = 6 : x = - 3

The solutions to the system of equations are:

t = 4, x = - 3, y = 3, z = - 2

4 x + 2 y = - 2, 2 x + 3 y = - 3

1 - s = \frac{3}{5} \cdot t, \frac{2}{3} \cdot s = 1 - t

3 x + 2 y = - 1, 5 x + y = - 4

2 x + 3 y = 6, 4 x + y = 2

3 x - y = 5, 2 x - 3 y = 8

What is x+y-z+t=6,y+z=1,z+2t=6,2t=8 ?
The solution to x+y-z+t=6,y+z=1,z+2t=6,2t=8 is t=4,x=-3,y=3,z=-2