What is (x/5)+y+2=0,(x/3)-y-10=0 ?

The solution to (x/5)+y+2=0,(x/3)-y-10=0 is x=15,y=-5

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(x/5)+y+2=0,(x/3)-y-10=0

(\frac{x}{5}) + y + 2 = 0, (\frac{x}{3}) - y - 10 = 0

x = 15, y = - 5

Solution steps

[(\frac{x}{5}) + y + 2 = 0 (\frac{x}{3}) - y - 10 = 0]

Isolate

x

for

(\frac{x}{5}) + y + 2 = 0 : x = - 5 y - 10

Substitute

x = - 5 y - 10

[\frac{- 5 y - 10}{3} - y - 10 = 0]

Simplify

[\frac{- 8 y - 10}{3} - 10 = 0]

Isolate

y

for

\frac{- 8 y - 10}{3} - 10 = 0 : y = - 5

For

x = - 5 y - 10

Substitute

y = - 5

x = - 5 (- 5) - 10

- 5 (- 5) - 10 = 15

x = 15

The solutions to the system of equations are:

x = 15, y = - 5

a = - 3, b = - 6, c = - 2

x - y = z, y = 4 z, x + y = 81

a + b = 3, b + c = 4, c + a = 5

2 x - 3 y = - 16, 5 x + 3 y = 2

9 x - 4 y = 23, 2 x - y = 12

What is (x/5)+y+2=0,(x/3)-y-10=0 ?
The solution to (x/5)+y+2=0,(x/3)-y-10=0 is x=15,y=-5