What is 3x+4y+10=0,x-y=2 ?

The solution to 3x+4y+10=0,x-y=2 is x=-2/7 ,y=-16/7

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3x+4y+10=0,x-y=2

3 x + 4 y + 10 = 0, x - y = 2

x = - \frac{2}{7}, y = - \frac{16}{7}

Solution steps

[3 x + 4 y + 10 = 0 x - y = 2]

Isolate

x

for

3 x + 4 y + 10 = 0 : x = \frac{- 4 y - 10}{3}

Substitute

x = \frac{- 4 y - 10}{3}

[\frac{- 4 y - 10}{3} - y = 2]

Simplify

[\frac{- 7 y - 10}{3} = 2]

Isolate

y

for

\frac{- 7 y - 10}{3} = 2 : y = - \frac{16}{7}

For

x = \frac{- 4 y - 10}{3}

Substitute

y = - \frac{16}{7}

x = \frac{- 4 ( - \frac{16}{7} ) - 10}{3}

\frac{- 4 ( - \frac{16}{7} ) - 10}{3} = - \frac{2}{7}

x = - \frac{2}{7}

The solutions to the system of equations are:

x = - \frac{2}{7}, y = - \frac{16}{7}

2 x + 3 y = 20, x - 2 y = 3

x + 4 y - 8 z = - 8, 4 x + 8 y - z = 76, 8 x - y - 4 z = 110

3 x + 5 y = 2, 9 x - y = - 1

2 x + 6 y = 22, 5 x - 2 y = 4

x + y = 3, 2 x + y = 2