What is (12)/x+5/y =-13/2 ,(18)/x+7/y =-19/2 ?

The solution to (12)/x+5/y =-13/2 ,(18)/x+7/y =-19/2 is

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(12)/x+5/y =-13/2 ,(18)/x+7/y =-19/2

\frac{12}{x} + \frac{5}{y} = - \frac{13}{2}, \frac{18}{x} + \frac{7}{y} = - \frac{19}{2}

(x = - 3, y = - 2)

Solution steps

[\frac{12}{x} + \frac{5}{y} = - \frac{13}{2} \frac{18}{x} + \frac{7}{y} = - \frac{19}{2}]

Isolate

x

for

\frac{12}{x} + \frac{5}{y} = - \frac{13}{2} : x = - \frac{24 y}{10 + 13 y}; y \neq = - \frac{10}{13}

Plug the solutions

x = - \frac{24 y}{10 + 13 y}

into

\frac{18}{x} + \frac{7}{y} = - \frac{19}{2}

For

\frac{18}{x} + \frac{7}{y} = - \frac{19}{2}

, subsitute

x

with

- \frac{24 y}{10 + 13 y} : y = - 2

Plug the solutions

y = - 2

into

\frac{12}{x} + \frac{5}{y} = - \frac{13}{2}

For

\frac{12}{x} + \frac{5}{y} = - \frac{13}{2}

, subsitute

y

with

- 2 : x = - 3

Verify solutions by plugging them into the original equations

Therefore, the final solution for

\frac{12}{x} + \frac{5}{y} = - \frac{13}{2}, \frac{18}{x} + \frac{7}{y} = - \frac{19}{2}

(x = - 3, y = - 2)

x + y = 3, 2 x + y = 3

- 10 x - 5 y = 2, 1 x - 7 y = 28

3 a + 5 b = 2, 6 a + 5 b = 22

x + 3 y = - 8, 4 x - 5 y = 2

x - 3 y - 3 = 3, x - 9 y - 2 = 0

What is (12)/x+5/y =-13/2 ,(18)/x+7/y =-19/2 ?
The solution to (12)/x+5/y =-13/2 ,(18)/x+7/y =-19/2 is