What is 7m+10n=77,3m+4n=32 ?

The solution to 7m+10n=77,3m+4n=32 is m=6,n= 7/2

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7m+10n=77,3m+4n=32

7 m + 10 n = 77, 3 m + 4 n = 32

m = 6, n = \frac{7}{2}

Solution steps

[7 m + 10 n = 77 3 m + 4 n = 32]

Isolate

m

for

7 m + 10 n = 77 : m = \frac{77 - 10 n}{7}

Substitute

m = \frac{77 - 10 n}{7}

[3 \cdot \frac{77 - 10 n}{7} + 4 n = 32]

Simplify

[\frac{231 - 2 n}{7} = 32]

Isolate

n

for

\frac{231 - 2 n}{7} = 32 : n = \frac{7}{2}

For

m = \frac{77 - 10 n}{7}

Substitute

n = \frac{7}{2}

m = \frac{77 - 10 \cdot \frac{7}{2}}{7}

\frac{77 - 10 \cdot \frac{7}{2}}{7} = 6

m = 6

The solutions to the system of equations are:

m = 6, n = \frac{7}{2}

3 x + 2 y = 5, 2 x - y = 8

2 x + y = 3, y - x = - 5

x = 4, y = 3

\frac{2}{( 3 x )} = 4, m - 5 = \frac{2}{7}

m + 2 n = 4, 3 m - m = 16