What are the solutions to the equation x^2+4x-3=0 ?

The solutions to the equation x^2+4x-3=0 are x=-2+sqrt(7),x=-2-sqrt(7)

Find the zeros of x^2+4x-3=0

The zeros of x^2+4x-3=0 are x=-2+sqrt(7),x=-2-sqrt(7)

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x^{2} + 4 x - 3 = 0

x = - 2 + 7, x = - 2 - 7

Solution steps

x^{2} + 4 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 3) = 27

x_{1, 2} = \frac{- 4 \pm 2 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 7}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 7}{2 \cdot 1}

x = \frac{- 4 + 2 7}{2 \cdot 1} : - 2 + 7

x = \frac{- 4 - 2 7}{2 \cdot 1} : - 2 - 7

The solutions to the quadratic equation are:

x = - 2 + 7, x = - 2 - 7

r^{2} - 10 r + 24

x^{2} = 8 x - 25

2 f + 4 > - 7 f + 3

\frac{- 5 + i}{2 i}

4 ∣ x - 5 ∣ + 1 \leq 3

What are the solutions to the equation x^2+4x-3=0 ?
The solutions to the equation x^2+4x-3=0 are x=-2+sqrt(7),x=-2-sqrt(7)
Find the zeros of x^2+4x-3=0
The zeros of x^2+4x-3=0 are x=-2+sqrt(7),x=-2-sqrt(7)